200W 3-Phase AC Gear Motor, Horizontal, Ratio 3~100

Low rpm 3-phase AC motor adds reduction gearbox working at 200W power. Gear ratios 3:1 to 100:1 to choose, corresponding speed rpm value 465~15, horizontal or vertical mounting direction. A brake is recommended to be used with the electric geared motor, for stopping machine safely.

Basic Specification

Model	SCJ009241（(Ratio:3~10) , SOCOJE-CH22-200（(Ratio:15~90), SOCOJE-CH28-200（(Ratio:100~200)
Rated Power	200W
Rated Voltage	Single-phase 110V, 50/60Hz Single-phase 220V, 50/60Hz 3-phase 220V, 50/60Hz 3-phase 380-415V, 50/60Hz
Gear Ratio	3:1/ 5:1/ 10:1/ 15:1/ 20:1/ 25:1/ 30:1/ 40:1/ 45:1/ 50:1/ 60:1/ 70:1/ 80:1/ 90:1/ 100:1
Working Efficiency	75%
Insulation Grade	Class B, Class F can be customized
Protection Grade	IP54
Duty	Continuous running
Working Environment	Temperature 10℃~+40℃ Humidity ≤90%
Pole	4P (6P)
Working Height	≤1000m
Standard	GB755/IEC-60034
Download Attachments	200W 3 Phase AC Gear Motor Datasheet

Terminal Box Direction (From Output Shaft)

AC Gear Motor Standard Installation

• All the SOCOJE 3-phase AC gear motors are suitable for this installation method, as shown in the following diagram.
• In the diagram, Q1, Q4, Q7, Q8 are the standard types of oil hole direction. If you need the air hole be on a special position, please contact us to modify the air hole direction.
• In actual use, it is recommended to pull out the oil plug in the air hole to balance the pressure in gearbox.

Details

Tips: How to calculate torque for 3-phase AC gear motor?

After calculating the gear ratio, convert the torque using the conditions of the machine used.

1. First, calculate the torque of the conveyor pulley (T1)
   T1 = (μ × load × roller radius) ÷ η1
2. Convert the result into the torque required by AC gear motor output shaft (T2)
   T2 = (T1 × sprocket reduction ratio) ÷ η2

Calculation example

1. T1 = μ × W (D/2) ÷ η1
   = 0.15 × 600 × (0.2/2) ÷ 0.95 = 9.5kgf-m
2. T2 = (T1 × 1/2) ÷ η2
   = (9.5 × 1/2) ÷ 0.9 = 5.28kgf-m